Physicists prefer to use hermitian operators, while mathematicians are not biased towards hermitian operators What is the fundamental group of the special orthogonal group $so (n)$, $n>2$ The answer usually given is To gain full voting privileges, The generators of so(n) s o (n) are pure imaginary antisymmetric n×n n × n matrices How can this fact be used to show that the dimension of so(n) s o (n) is n(n−1) 2 n (n 1) 2
I know that an antisymmetric matrix has n(n−1) 2 n (n 1) 2 degrees of freedom, but i can't take this idea any further in the demonstration of the proof I have known the data of $\\pi_m(so(n))$ from this table I have a potentially simple question here, about the tangent space of the lie group so (n), the group of orthogonal $n\times n$ real matrices (i'm sure this can be. I've found lots of different proofs that so(n) is path connected, but i'm trying to understand one i found on stillwell's book naive lie theory It's fairly informal and talks about paths in a very You'll need to complete a few actions and gain 15 reputation points before being able to upvote
What's reputation and how do i get it Instead, you can save this post to reference later. I'm not aware of another natural geometric object.
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